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Write the equation in slope-intercept form of the line that has a slope of 6 and contains the point (1, 1)

Sagot :

y=ax+b 
slope is 6 so y=6x+b
point is putting to y=6x+b
1=6*1+b
b=-5
y=6x-5
[tex]m=6 , \ \ \ (1, 1) \\ \\To \ find \ our \ equation \ we \ will \ use \ the \ formula: \\ \\ y - y _{1} = m(x - x _{1}), wherem \ is \ the \ slope \ and \ (x _{1}, y _{1}) \ is \ the \ point \\ \\m=6 , \ \ x_{1}=1 , \ \ y_{1} = 1\\\\y - 1 = 6(x-1)\\\\y-1=6x -6 \\\\y=6x-6+1\\\\y=6x-5[/tex]