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use the Binomial Theorem to expand (x - 2y)^3

Sagot :

Konrad509idn
[tex](x-2y)^3=x^3-6x^2y+12xy^2-8y^3[/tex]
Luanaidn

From Binomial Theorem (x-2y)³:
([tex] (\frac{3}{0}) x^{3}+( \frac{3}{1} ) x^{2} *(-2y)+( \frac{3}{2})x*( -2y)^{2} +( \frac{3}{3}) x^{0} (-2y)^{3} =[/tex][tex] \frac{3!}{0!3!} x^{3}- \frac{3!}{1!2!} x^{2} 2y- \frac{3!}{2!1!}x4 y^{2}- \frac{3!}{3!0!}8 y^{3} [/tex]=x³-6x²y-12xy²-8y³
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