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Sagot :
[tex]cos 2x=1-2sin^2x \\ cos 45^0=1-2sin^2(22,5)^0 \\ \frac{ \sqrt{2} }{2} =1-2sin^2(22,5)^0 \to sin(22,5)^0= \frac{ \sqrt{2- \sqrt{2} } }{2} [/tex]
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