a)y=-6x+4
Slope and intercept a=-6 b=4
equation for new line:
y=cx+d
If new line is parallel c=a=-6 so
y=-6x+d
We substitude point (2,10)
10=-6*2+d /+12
d=22
so y=-6x+22
b)
y=-[tex] \frac{2}{3} [/tex]x-5
a=-2/3
b=-5
new line:
y=ex+f
If line is perpendicular e=-[tex] \frac{1}{a} [/tex]
so e=[tex] \frac{3}{2} [/tex]
we can write
y=[tex] \frac{3}{2}x+f [/tex]
Substituting point (6,3)
3=[tex] \frac{3}{2}*6+f [/tex]
f=3-9
f=-6
y=[tex] \frac{3}{2}x-6 [/tex]
