Explore IDNLearn.com's extensive Q&A database and find the answers you're looking for. Get accurate and detailed answers to your questions from our dedicated community members who are always ready to help.
The density of aluminum is 2.70 g/cm3. Apiece of aluminum foil that is 1000 cm on each side has a mass of 440. mg. How thick is the piece of foil?
mass/volume = density mass = (440 mg)*(1g)/(1000mg) = 0.440g volume = (1000cm)(1000cm)(t) where t = thickness density = 2.70 g/cm^3 = (0.440g)/((1000cm)(1000cm)(t))
multiply both sides by 't' and divide both sides by (2.70g/cm^3)
t = (0.440) / ((1000cm)(1000cm)(2.70)) = 1.629x10^-7 cm
t = (1.629 x 10^-7 cm)*(1000000 micrometers)/(1 cm) = 0.1629 micrometers
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Thank you for visiting IDNLearn.com. We’re here to provide clear and concise answers, so visit us again soon.
