Answered

Get detailed and accurate responses to your questions with IDNLearn.com. Find the answers you need quickly and accurately with help from our knowledgeable and experienced experts.

What is the probability of not drawing a green marble from a jar containing 7 red, 4 green, 3 white, and 9 blue marbles?

Sagot :

Iloveonedirectionidn
[tex]7+4+3+9[/tex]
[tex]11+12[/tex]
[tex]23[/tex]

[tex] \frac{23}{23} - \frac{4}{23} [/tex]

[tex] \frac{23-4}{23} [/tex]

[tex] \frac{19}{23} [/tex] [tex]chance[/tex]

Answer:

Probability of not drawing a green marble is 19/23.

Step-by-step explanation:

A jar is containing 7 red, 3 white, and 9 blue marbles.

Then the probability to draw a green marble will be = Numbers of green marbles/ Total numbers of marbles of all colors

P(G) = 4/(7 + 4 + 3 + 9)

P(G) = 4/23

Now the probability of not drawing a green marble = 1 - probability of drawing a green ball

P = 1 - 4/23 = 19/23

Therefore answer is 19/23.

Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. Accurate answers are just a click away at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.