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check whether 6n can never end with the digit 2 for any natural number n

Sagot :

6 x   2 =   12
6 x   7 =   42
6 x 12 =   72
6 x 17 = 102

For any 'n' equal to ( 2 + any multiple of 5), 6n ends with the digit '2' .

The conjecture appears to be pretty well shot.

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