IDNLearn.com offers a user-friendly platform for finding and sharing answers. Join our Q&A platform to access reliable and detailed answers from experts in various fields.
Sagot :
[tex]b-boys\\g-girls\\\\ \left\{\begin{array}{ccc}b+g=51\\2g=b+12\end{array}\right\\\\+\left\{\begin{array}{ccc}b+g=51\\2g-b=12\end{array}\right\\----------\\.\ \ \ \ \ \ 3g=63\ \ \ \ /:3\\.\ \ \ \ \ \ g=21\\\\Answer:21\ girls.[/tex]
x- amount of girls
y-amount of boys
x+y=51
y+12=2*x
From first equation:
x=51-y
substitude to second:
y+12=2*(51-y)
y+12=102-2y
3y=102-12
3y=90 /:3
y=30
x=51-30=21
There are 21 girls.
y-amount of boys
x+y=51
y+12=2*x
From first equation:
x=51-y
substitude to second:
y+12=2*(51-y)
y+12=102-2y
3y=102-12
3y=90 /:3
y=30
x=51-30=21
There are 21 girls.
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.