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The variables x and y are inversely proportional, and y = 2 when x = 3. What is the value of y when x = 9?

Sagot :

y=k/x
2=k/3
k=6
y=6/x
y=6/9=2/3
[tex]If\ x\ and\ y\ are\ inversely\ proportional\ then\ xy\ is\ constans.\\\\9y=2\times 3\\\\9y=6\ \ \ \ \ \ /:9\\\\y=\frac{6}{9}\\\\y=\frac{2}{3}[/tex]
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