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how many occupied orbitals does a fluorine atom contain in the ground state?
Well, the configuration is [tex]1s^22s^22p^5[/tex]. To show the electrons, we have 1s as [**], 2s as [**], 2p as [**][**][*-], where * is an electron and - is a vacant slot. We have 5 occupied orbitals (4 fully occupied, one partially occupied)
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