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The sum of 3 consecutive odd integers is 87.Find the equation used to solve this problem and the three integers.
the first odd integer is x. The next odd integer will be x+2. and the next is x+4. Then we can say that (x)+(x+2)+(x+4)=87 working that out yields 3x+6=87 and thus 3x=81 and by consequence x=27
Let be y - 2, y and y + 2 the 3 consecutives odd integers; There sum is 3y, and, in the same time is 87 => y = 87/3 => y = 29 => y - 2 = 27; y + 2 = 31; The 3 integers are : 27, 29, 31.
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