IDNLearn.com: Your one-stop destination for finding reliable answers. Our experts are available to provide in-depth and trustworthy answers to any questions you may have.
Sagot :
[tex]x^2-6x+6=0\\
x^2-6x+9-3=0\\
(x-3)^2=3\\
x-3=\sqrt 3 \vee x-3=-\sqrt3\\
x=3+\sqrt3 \vee x=3-\sqrt3[/tex]
[tex]x^2-6x+6=0 \\ \\a=1, \ \ b=-6, \ \ c=6 \\\\\Delta =b^2-4ac = (-6)^2 -4\cdot1\cdot 6 = 36-24=12\\\\\sqrt{\Delta }=\sqrt{12}=\sqrt{4\cdot 3}=2\sqrt{3}\\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{6-2\sqrt{3}}{2 }=\frac{2( 3- \sqrt{3})}{2}= 3- \sqrt{3}\\\\x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{6+2\sqrt{3}}{2 }=\frac{2( 3+ \sqrt{3})}{2}= 3+ \sqrt{3}[/tex]
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for solutions ends here at IDNLearn.com. Thank you for visiting, and come back soon for more helpful information.