Answered

Connect with experts and get insightful answers on IDNLearn.com. Ask anything and get well-informed, reliable answers from our knowledgeable community members.

the combustion of propane may be described by the chemical equation, 

C3H8(g) + 5O2(g) --> 3CO2(g) + 4H2O(g) 

how many grams of O2(g) are needed to completely burn 40.4 g of C3H8(g)?

Sagot :

[tex]\nu_{C_3H_8}=\frac{40.4}{\mu_{C_3H_8}}=[/tex]
[tex]=\frac{40.4}{3A_C+8A_H}=\frac{40.4}{44}=[/tex]
[tex]=\frac{9}{10}=0.9mol[/tex]
[tex]1mol\ C_3H_8...5\ mol\ O_2 \\ 0.9mol\ C_3H_8...x\ mol\ O_2[/tex]
[tex]x=\frac{0.9*5}{1}=4.5mol\ O_2[/tex]
[tex]m=\mu_{O_2}*x=2*A_O*4.5=9*8=72g\ O_2[/tex]
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.