IDNLearn.com makes it easy to find answers and share knowledge with others. Discover in-depth and trustworthy answers from our extensive network of knowledgeable professionals.
Sagot :
[tex]x^2+10x+25=9\\\\\underbrace{x^2+2x\cdot5+5^2}_{(*)}=9\\\\(x+5)^2=9\iff x+5=3\ or\ x+5=-3\\\\x=3-5\ or\ x=-5-3\\\\\boxed{x=-2\ or\ x=-8}\leftarrow solutions[/tex]
[tex](*)\ (a+b)^2=a^2+2ab+b^2[/tex]
[tex]other\ methode:\\\\x^2+10x+25=9\\\\x^2+10x+25-9=0\\\\x^2+10x+16=0\\\\x^2+2x+8x+16=0\\\\x(x+2)+8(x+2)=0\\\\(x+2)(x+8)=0\iff x+2=0\ or\ x+8=0\\\\\boxed{x=-2\ or\ x=-8}[/tex]
[tex](*)\ (a+b)^2=a^2+2ab+b^2[/tex]
[tex]other\ methode:\\\\x^2+10x+25=9\\\\x^2+10x+25-9=0\\\\x^2+10x+16=0\\\\x^2+2x+8x+16=0\\\\x(x+2)+8(x+2)=0\\\\(x+2)(x+8)=0\iff x+2=0\ or\ x+8=0\\\\\boxed{x=-2\ or\ x=-8}[/tex]
[tex]x^2+10x+25=9\\
(x+5)^2=9\\
x+5=3 \vee x+5=-3\\
x=-2 \vee x=-8[/tex]
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.