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Sagot :
v=6, w=1
[tex]\frac{2w+3v}{v^2}=\frac{2*1+3*6}{6^2}=\frac{2+18}{36}=\frac{20}{36}=\frac{5}{9}=0.(5)[/tex]
[tex]\frac{2w+3v}{v^2}=\frac{2*1+3*6}{6^2}=\frac{2+18}{36}=\frac{20}{36}=\frac{5}{9}=0.(5)[/tex]
Answer:
[tex] \frac{2w+3v}{ v^{2} }} = \frac{2(1)+3(6)}{36}= \frac{20}{36}= \frac{10}{18}= \frac{5}{9} [/tex]
[tex] \frac{2w+3v}{ v^{2} }} = \frac{2(1)+3(6)}{36}= \frac{20}{36}= \frac{10}{18}= \frac{5}{9} [/tex]
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