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Given: ABCD is a kite
AB=CB
AD=DC angleB=120
The circle has radius 3 Find: perimeter of ABCD
if angleb is 120 then AC is 120*2 = 240. 360-240 = 120 , 120/2 = 60 . If AB = 60 , angle adb is 30 and angle bdc is 30. DB is 2 * radius because angleA is 90. So with Pisagor AB = 3 , BC = 3 , AD = 3root3 and DC is 3root3.
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