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Two angles are supplementary. One angle measures 16 degrees less than 3 times the other. Find the measure of each angle.

Sagot :

Y = 1st angle
X = 2nd angle

Y = 3X - 16

90 = X + Y

90 = X + (3X -16)

Do some algebra and X=26.5

So substitute x back in to find y, and Y=63.5
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Answer:

Two angles are supplementary one angle is 4 degrees less than three times the other find the measures of the angles

x + y = 180

x = 3y - 4

3y - 4 + y = 180

4y = 184

y = 46

x = 134

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