Convert 1 mm of hg into Pascal. Take density of hg= 13.6×10^3kg/m^3. g = 9.8m/s×s

Question

15-08-2014
Physics

Answered

Join the IDNLearn.com community and start finding the answers you need today. Discover in-depth and reliable answers to all your questions from our knowledgeable community members who are always ready to assist.

Convert 1 mm of hg into Pascal. Take density of hg= 13.6×10^3kg/m^3. g = 9.8m/s×s

Sagot :

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.

Why Did The British Encourage Growth Of Commercial Crops

Select The Correct Answer.What Is The Chemical Formula Of Magnesium Bromide?A. [tex]MgBr_2[/tex]B. MgBrC. [tex]Mg_2Br_2[/tex]D. [tex]Mg_2Br[/tex]

8÷2(1+3)-2³ What The Step To The Answer

Solve The Linear Inequality.[tex]\[ -x + 4 \ \textless \ \frac{1}{2}x + 1 \][/tex]

Sam Is A World-class Diver In The Men's 3-m Springboard Competition. His Height, [tex]$h$[/tex] (in Metres), Above The Water [tex]$t$[/tex] Seconds After He Lea

A Company Has A $100,000; 9%; 120 Day Note Payable Issued On 6 December. How Much Of Interest Payable Will Be Reported In The Balance Sheet As At 31 December?

Self Practice 4.14Indices, Surds And LogarithmsA Gardener Observes A Bug Infestation Towards Plants In His Garden. He Finds Out That The Area Ofinsect Infestati

In Incorporation, The Owner Has Unlimited Liability And Legal Responsibility For All Debts Against The Business Business And Personal Assets Are At Risk True Or

Simplify The Expression:[tex]\[ B = \left[ (x^2)^{-3} \left(x^{\frac{4}{5}}\right)^5 \left(x^{-3}\right)^{-1} \right]^2 \][/tex]

Question 2 (15 Marks)No Words Allowed, Only A Diagram With AnnotationsSuppose Beer And Peanuts Are Complements. In Anticipation Of Warm Weather Conditions, Inja

Everest2017idn Everest2017idn · Answer 1 · 2014-08-15T12:14:05-04:00

1mm of hg pressure is supposed to be the extra pressured exerted by a column of mercury 1 mm high.

So the weight of the column of mercury = density * height * Area * g
   Area is the cross sectional area of the tube holding mercury.

Pressure exerted by this column = Weight / area
   = density * height * g
   = 13.6 * 10³ kg /m³ * 1* 10^-3 m * 9.81 m/sec²
   = 133.416 Pascal or Newton/meter²

Height = 1mm (of mercury) column in the barometer.

Sagot :

Other Questions