From tech troubles to travel tips, IDNLearn.com has answers to all your questions. Discover comprehensive answers to your questions from our community of experienced professionals.
Sagot :
[tex]4x + 8y = 10\\ 4x - 2y = 21 \\ \\ 8y =-4x+10 \ \ /:8 \\ -2y=-4x+21\ \ / : (-2)\\ \\y =-\frac{4}{8}x+\frac{10}{8}\\y=2x-\frac{21}{2}[/tex]
[tex]y =-\frac{1}{2}x+\frac{5}{4}\\y=2x-10.5\\\\ a_{1}\cdot a_{2}=-1\\m_{1}=-\frac{1}{2}, \ \ m_{2}=2 \\ m _{1}*m _{2} = -1 \ it \ perpendicular \ lines \ we \ have \\\\ m _{1}*m _{2} = -1\\\\-\frac{1}{2}\cdot 2 = -1\\-1=-1 \\ \\L=R [/tex]
[tex]y =-\frac{1}{2}x+\frac{5}{4}\\y=2x-10.5\\\\ a_{1}\cdot a_{2}=-1\\m_{1}=-\frac{1}{2}, \ \ m_{2}=2 \\ m _{1}*m _{2} = -1 \ it \ perpendicular \ lines \ we \ have \\\\ m _{1}*m _{2} = -1\\\\-\frac{1}{2}\cdot 2 = -1\\-1=-1 \\ \\L=R [/tex]
[tex]k:\ \ \ 4x + 8y = 10\ \ \ \Rightarrow\ \ \ 8y=-4x+10\ \ \ \Rightarrow\ \ \ y=- \frac{1}{2}x+1 \frac{1}{4}\\\\ \Rightarrow\ \ \ m_ 1=- \frac{1}{2} \\\\l:\ \ \ 4x - 2y = 21\ \ \ \Rightarrow\ \ \ -2y=-4x+21\ \ \ \Rightarrow\ \ \ y=2x-10 \frac{1}{2} \\\\\Rightarrow\ \ \ m_2=2\\\\m_1\cdot m_2=(- \frac{1}{2} )\cdot2=-1\ \ \ \Rightarrow\ \ \ k\ \perp\ l\\\\Ans.\ The\ lines\ are\ perpendicular.[/tex]
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find clear and concise answers at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.