can someone help me with this problem

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16-08-2014
Mathematics

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can someone help me with this problem

Sagot :

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Konrad509idn Konrad509idn · Answer 1 · 2014-08-16T12:50:04-04:00

Konrad509idn Konrad509idn

16-08-2014

[tex]180-127=53\\\\ 53+x+7+2x=180\\ 3x=120\\ x=40\\\\ m\angle A=2x=2\cdot40=80^{\circ}[/tex]

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Анонимidn Анонимidn · Answer 2 · 2014-08-16T12:53:29-04:00

Анонимidn Анонимidn

16-08-2014

[tex]Look\ at\ the\ picture.\\\\127^o+z=180^o\ \ \ \ \ |subtract\ 127^o\ from\ both\ sides\\\\z=53^o\\\\z+x+7^o+2x=180^o\\\\53^o+3x+7^o=180^o\\\\60^o+3x=180^o\ \ \ \ \ |subtract\ 60^o\ from\ both\ sides\\\\3x=120^o\ \ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\x=40^o\\\\m\angle A=2\times40^o=80^o[/tex]

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