Explore IDNLearn.com's extensive Q&A database and find the answers you need. Ask your questions and receive prompt, detailed answers from our experienced and knowledgeable community members.
Sagot :
[tex]\frac{1}{14}(3x-2)=\frac{x+10}{10}\ \ \ \ \ |multiply\ both\ sides\ by\ 140\\\\10(3x-2)=14(x+10)\\\\30x-20=14x+140\\\\30x-14x=140+20\\\\16x=160\\\\x=160:16\\\\\boxed{x=10}[/tex]
[tex] \frac{1}{14}(3x-2)=\frac{x+10}{10} \ \ / \cdot 140\\\\140\cdot \frac{1}{14}(3x-2)=140\cdot\frac{x+10}{10}\\ \\10(3x-2)=14(x+10)\\\\30x-20 =14x+140\\\\30x-14x=140+20\\ \\16x=160 \ \ /:16\\ \\x=10[/tex]
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.