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find the inverse of the function: f(x)= 2x-3/x+1
I need the steps to solve for y I get stuck after I multiply both sides by y+1


Sagot :

[tex]f(x)=\frac{2x-3}{x+1}\\\\ y=\frac{2x-3}{x+1}\\\\ y(x+1)=2x-3\\\\yx+y=2x-3\\\\yx-2x=-3-y\\\\x(y-2)=-3-y\\\\ x=\frac{-3-y}{y-2}\\\\ f(x)=\frac{-3-y}{y-2}[/tex]