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Sagot :
3x+15=3(x+5)
3x+15=3x+15
3x-3x=15-15
Therefore x can be equal to any value.
3x+15=3x+15
3x-3x=15-15
Therefore x can be equal to any value.
[tex]3x+15=3(x+5)\\\\
3x+15=3x+3*5\\\\
3x+15=3x+15\\\\0=0\\\\LHS=RHS\\\\ There\ are\ infinitely\ many\ solutions. [/tex]
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