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Points A, B and C are collinear. Point B is between Point A and Point C. Find the length of BC if BC=3x-2, AB=12, and AC=5x+2.
A very simple drawing of this problem would be something like A---B-------C B is somewhere in the middle, we don't know yet. But a simple fact that you can get out of the picture is that AC - BC = AB, or (5x+2) - (3x-2) = 12. Solve: 2x + 4 = 12 2x = 8 x = 4 Plug in x=4 for BC: 3x-2 = 3(4) - 2 = 12 - 2 = 10 BC is therefore 10 units long.
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