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The equation is: Point K is between points J and L. If JK= x^2-4x, KL= 3x-2 and JL=28, find the lengths of JK and KL
you would take x^2-4x+3x-2=28 add common numbers x^2-x-2=28 set it equal to 0 x^2-x-30 use the quadratic formula x=1+-√1-4(1)(-30)÷2 Solve for x 1+-√131÷2 X÷≈6.223 plug x into both equations for kl and jl and you will get lenghts that are ≈13.829 for Jk and ≈16.669 for KL
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