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Sagot :
lenght spaghetti chef a:
503 2/3ft= (503*3+2)/3=1511/3 =503,(6)
lenght spaghetti chef b:
503,66
Because 503,(6)>503,66
=> lenght spaghetti chef a > lenght spaghetti chef b
So, the winner must be chef a, but, if 503.66 rounds to 503.7, also 503(6) rounds to 503.7, and in this case
lenght spaghetti chef a= lenght spaghetti chef b
So, chef a should protest the judges' decision, because his lenght spaghetti is ≥ lenght spaghetti chef b.
503 2/3ft= (503*3+2)/3=1511/3 =503,(6)
lenght spaghetti chef b:
503,66
Because 503,(6)>503,66
=> lenght spaghetti chef a > lenght spaghetti chef b
So, the winner must be chef a, but, if 503.66 rounds to 503.7, also 503(6) rounds to 503.7, and in this case
lenght spaghetti chef a= lenght spaghetti chef b
So, chef a should protest the judges' decision, because his lenght spaghetti is ≥ lenght spaghetti chef b.
[tex] \frac{2}{3} =0.666666... = 0.67[/tex]
Chef A Length >=< Chef B Length
[tex]503 \frac{2}{3} [/tex] >=< [tex]503.66[/tex]
[tex]503.67[/tex] = [tex]503.67[/tex]
If you convert [tex] \frac{2}{3} [/tex] into a decimal and round it, it shows that both the chefs have the the same length of pasta.
Chef A Length >=< Chef B Length
[tex]503 \frac{2}{3} [/tex] >=< [tex]503.66[/tex]
[tex]503.67[/tex] = [tex]503.67[/tex]
If you convert [tex] \frac{2}{3} [/tex] into a decimal and round it, it shows that both the chefs have the the same length of pasta.
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