Answered

Get expert advice and community support on IDNLearn.com. Discover prompt and accurate responses from our experts, ensuring you get the information you need quickly.

A shopper in a supermarket pushes a loaded cart with a horizontal force of 13.3 Newtons. The cart has a mass of 25.1 kg and is pushed for 3.60 seconds, starting from rest?
(a) How far (in meters) will the cart move during these 3.60 seconds. (Ignore friction.)
m



(b) How far (in meters) will the cart move in the 3.60 second interval if the shopper places her 27.4-N child in the cart before she begins to push it?
m

Sagot :

Ewanidn
a) S(displacement)=ut+1/2at^2  a=f/m
 thus s=1/2(13.3/25.1)(3.6)^2   ut dissapear because u=0
s=3.43m

b) the inertia has increased because the mass increases:
m(kart+child)=(245.98+27.4)/9.8
m=27.896
s=ut+1/2at^2
s=1/2(13.3/27.899)(3.6)
s=3.09m
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.