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How do you solve x-8= -(12/x)

Sagot :

Konrad509idn
[tex]x\not=0\\ x-8= -\frac{12}{x}|\cdot x\\ x^2-8x=-12\\ x^2-8x+12=0\\ x^2-6x-2x+12=0\\ x(x-6)-2(x-6)=0\\ (x-2)(x-6)=0\\ x=2 \vee x=6 [/tex]
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