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What is the acceleration of a 6.4 kilogram bowling ball if a force of 12 N is applied to it?

Sagot :

F=ma
12=6.4a
1.875=a
A=1.875

Answer:

1.875 m/sec2

Explanation:

Acceleration = Force/Mass

Acceleration = 12/6.4

12/6.4 = 1.875

Units = m/sec2

1875 m/sec2