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Sagot :
Area = Length × Width
60 3/8 = (5 1/2 × w) + (6 × w)
60 3/8 = 11 1/2 + 2w
48 7/8 = 2w
24 7/16 = w
Width: 24 7/16
60 3/8 = (5 1/2 × w) + (6 × w)
60 3/8 = 11 1/2 + 2w
48 7/8 = 2w
24 7/16 = w
Width: 24 7/16
By definition, the area of a rectangle is:
[tex] A = w * l
[/tex]
Where,
w: width of the rectangle
l: length of the rectangle
The total area is given by:
[tex] A = A1 + A2
[/tex]
Where,
A1: rectangular wooden board 1
A2: rectangular wooden board 2
Substituting we have:
[tex] 60 \frac{3}{8} = (6) (w) + (5\frac{1}{2}) (w)
[/tex]
Rewriting we have:
[tex] \frac{483}{8} = (6) (w) + (\frac{11}{2}) (w)
[/tex]
[tex] 483 = 48w + 44w
483 = 92w
[/tex]
[tex] w = \frac{483}{92}
w = 5.25
[/tex]
[tex] w = 5 \frac{1}{4}
[/tex]
Answer:
The width is given by:
[tex] w = 5 \frac{1}{4}
[/tex]
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