Get detailed and reliable answers to your questions with IDNLearn.com. Discover in-depth and reliable answers to all your questions from our knowledgeable community members who are always ready to assist.

Eleanor and max used two rectangular wooden boards to make a set for the school play.one board was 6 feet long and the other board was 5 and 1/2 feet long. the two boards had equal widths .The total are off the set was 60 3/8 square feet.What was the width??

Sagot :

Area = Length × Width

60 3/8 = (5 1/2 × w) + (6 × w)
60 3/8 = 11 1/2 + 2w
48 7/8 = 2w
24 7/16 = w

Width: 24 7/16

By definition, the area of a rectangle is:

[tex] A = w * l
[/tex]

Where,

w: width of the rectangle

l: length of the rectangle

The total area is given by:

[tex] A = A1 + A2
[/tex]

Where,

A1: rectangular wooden board 1

A2: rectangular wooden board 2

Substituting we have:

[tex] 60 \frac{3}{8} = (6) (w) + (5\frac{1}{2}) (w)
[/tex]

Rewriting we have:

[tex] \frac{483}{8} = (6) (w) + (\frac{11}{2}) (w)
[/tex]

[tex] 483 = 48w + 44w

483 = 92w
[/tex]

[tex] w = \frac{483}{92}

w = 5.25

[/tex]

 [tex] w = 5 \frac{1}{4}
[/tex]

Answer:

The width is given by:

[tex] w = 5 \frac{1}{4}
[/tex]