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find the slope of the line (-3, -2) and (3, 4)

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Luanaidn
[tex]slope=\frac{y_2-y_1}{x_2-x_1}\\\\ (x_1,y_1)=(-3,-2)\\ (x_2,y_2)=(3,4)\\\\ slope=\frac{4+2}{3+3}=\frac{6}{6}=1\\\\ Slope\ is\ equal\ to\ 1. [/tex]
Porshiaidn
You do 4+2=6. Then, you do 3+3 which equals 6. Your problem would be 6/6 then, you simplify it.
Your answer is 1
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