Answered

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I want to prepare 4 Liters of 0.25 M aqueous sodium chloride solution. How many grams of the salt will I need to weigh out?

Sagot :

Neetooidn

Answer:

Mass = 58.5 g

Explanation:

Given data:

Volume of solution = 4 L

Molarity of solution = 0.25 M

Grams of NaCl required = ?

Solution:

Formula:

Molarity = number of moles / volume in L

By putting values,

0.25 M = number of moles / 4 L

Number of moles = 0.25 mol/L × 4 L

Number of moles = 1 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 1 mol × 58.5 g/mol

Mass = 58.5 g

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