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Two iron bolts of equal Mass one at a hundred see another at 55 Sierra place in the insulated cylinder assuming the heat capacity of the container is negligible what is the final temperature inside the container

Sagot :

Answer:

[tex]T_2 = 77.5c[/tex]

Explanation:

From the question we are told that

Temp of first bolts[tex]T_1=100[/tex]

Temp of 2nd bolt [tex]T_2=55[/tex]

Generally the equation showing the relationship between  heat & temperature is given by

  [tex]q=cm \triangle T[/tex]

Generally heat released  by the iron bolt  = heat gained by the iron bolt

Generally solving mathematically

     [tex]-(0.45*m* (T_2-100 \textdegree c)) = 0.45*m*(T_2 -55\textdegree c)[/tex]

     [tex]-(T_2-100 \textdegree c)) = (T_2 -55 \textdegree c)[/tex]

      [tex]T_2 +T_2= 100 \textdegree c+55 \textdegree c[/tex]

      [tex]T_2=\frac{155 \textdegree c}{2}[/tex]

      [tex]T_2 = 77.5 \textdegree c[/tex]

Therefore [tex]T_2 = 77.5 \textdegree c[/tex] is the final temperature inside the container