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HELP PLS ITS BEEN AN 3 HOURS

HELP PLS ITS BEEN AN 3 HOURS class=

Sagot :

Supernovaidn

Answer:

0.433 s

Explanation:

Let's break the projectile motion into its horizontal and vertical components:

Horizontal component (x):

  • 3.22 * cos(62.9)

Vertical component (y):

  • 3.22 * sin(62.9)

We want to find the time required for the hurdler to travel a distance of 0.635 m. In order words, his displacement should be 0.635 m in the x-direction.

Since we don't have the final velocity, we can use this constant acceleration equation:

  • Δx = v₀t + 1/2at²

We have three known variables and want to solve for t. Using this equation in the x-direction, we have:

  • Δx = 0.635 m
  • v₀ = 3.22 * cos(62.9)
  • a = 0 m/s²
  • t = ?

Substitute these values into the equation.

  • 0.635 = [3.22 * cos(62.9)] t + 1/2(0) t²

Simplify the equation.

  • 0.635 = 3.22 * cos(62.9) t  

Divide both sides by the horizontal component of the initial velocity.

  • 0.432899075 = t

Since we start with 3 sig figs, we will round this value to 0.433. The time it takes to clear the hurdle is 0.433 seconds.

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