Answer:
The average velocity of the car is 1.5 m/s
Step-by-step explanation:
The given parameters are;
The displacement of one of the cars north of the start after 5 seconds = 10 meters
The displacement of the car north of the start after 15 seconds = 25 meters
The average velocity of the cars [tex]\overline v[/tex] is given as follows;
[tex]\overline v = \dfrac{\Delta x}{\Delta t}[/tex]
Where;
Δx = The change in the displacement of the car = 25 m - 10 m = 15 m
Δt = The corresponding amount of the change in time 15 s - 5 s = 10 s
By substituting the known values of Δx and Δt in the equation for the average velocity of the car, [tex]\overline v[/tex], we have;
[tex]\overline v = \dfrac{15 \ m}{10 \ s} = 1.5 \ m/s[/tex]
∴ The average velocity of the car, [tex]\overline v[/tex] = 1.5 m/s
