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[tex]y-\dfrac{4}{12}=1\\\\y-\dfrac{4:4}{12:4}=1\\\\y-\dfrac{1}{3}=1\qquad|\text{add }\dfrac{1}{3}\ \text{to both sides}\\\\y-\dfrac{1}{3}+\dfrac{1}{3}=1+\dfrac{1}{3}\\\\y=1\dfrac{1}{3}[/tex]
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