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Answer:
let the coefficient of friction be ß
Explanation:
[tex]from \: third \: law \: of \: solid \: friction \\ friction = \beta \times R \\ where \: R \: is \: the \: normal \: reaction \\ 46 = 0.30 \times R \\ R = \frac{46}{0.30} \\ R = 153.33 \: N \\ but \: R = mg \\ where \: mg \: is \: the \: weight \\ hence \\ weight, W = 153.33 \: N[/tex]