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Find the equation of the line described.
Perpendicular to y = 3x + 6; passing through the point (4,5).
The line equation is y =


Sagot :

Answer:

y = - [tex]\frac{1}{3}[/tex] x + [tex]\frac{19}{3}[/tex]

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x + 6 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{3}[/tex] , thus

y = - [tex]\frac{1}{3}[/tex] x + c ← is the partial equation

To find c , substitute (4, 5) into the partial equation

5 = - [tex]\frac{4}{3}[/tex] + c ⇒ c = 5 + [tex]\frac{4}{3}[/tex] = [tex]\frac{19}{3}[/tex]

y = - [tex]\frac{1}{3}[/tex] x + [tex]\frac{19}{3}[/tex] ← equation of perpendicular line