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The expression 200 - 16t2 models the height in feet of an object that falls from the initial height of 200 feet t seconds after being dropped. Find the height of the object after 0.75 seconds. Make sure and include the units of feet in your answer for full credit. Round your answer to the nearest hundredth place.

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Answer:

Concept: Modeling expressions

  1. We are given the equation
  2. [tex]200 - 16 {t}^{2} [/tex]
  3. We want to find the time after 0.75 seconds given that t is represented in seconds.
  4. Hence we do
  5. [tex]200 - 16(0.75)^{2} [/tex]
  6. Hence we get the answer to 191 feet

The height of the object that falls after 0.75 seconds given that t is represented in seconds is 191 feet.

What is a quadratic equation?

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

The expression 200 - 16t^2 models the height in feet of an object that falls from the initial height of 200 feet t seconds after being dropped.

We need to find the time after 0.75 seconds given that t is represented in seconds.

The expression is given

[tex]200 - 16t^2[/tex]

time t = 0.75

Substitute the value of t in the given expression

= 200 - 16(0.75)^2

= 200 - 9

= 191

Hence we get the answer to 191 feet.

Learn more about quadratic equations;

brainly.com/question/13197897

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