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Answer the question above ​

Answer The Question Above class=

Sagot :

Answer:

[tex]tan\:\left(\frac{5\pi }{6}\right)=tan\left(-\frac{\pi }{6}\right)[/tex]

Option A is correct.

Step-by-step explanation:

We need to find equivalent of [tex]tan\:\left(\frac{5\pi }{6}\right)[/tex]

First we solve [tex]tan\:\left(\frac{5\pi }{6}\right)[/tex]

We get [tex]-\frac{1}{\sqrt{3} }[/tex]

Now checking all the options.

Option A: [tex]tan\:(-\frac{\pi}{6} )[/tex]

Solving [tex]tan\left(-\frac{\pi }{6}\right)\: we\: get\: \mathbf{ -\frac{1}{\sqrt{3} }}[/tex]

Option B: [tex]tan\left(\frac{7\pi }{6}\right)[/tex]

Solving [tex]tan\left(\frac{7\pi }{6}\right)\: we\: get\: \mathbf{\frac{1}{\sqrt{3} }}[/tex]

Option C: [tex]cot\left(\frac{5\pi }{6}\right)[/tex]

Solving [tex]cot\left(\frac{5\pi }{6}\right)\:we\:get\:\mathbf{-\sqrt{3} }[/tex]

Option D : [tex]tan\left(-\frac{5\pi }{6}\right)[/tex]

Solving [tex]tan\left(-\frac{5\pi }{6}\right) \:we\:get:\mathbf{\frac{1}{\sqrt{3} } }[/tex]

So, looking at the options, only Option A has the same result as given question

So, [tex]tan\:\left(\frac{5\pi }{6}\right)=tan\left(-\frac{\pi }{6}\right)[/tex]

Option A is correct.

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