Amirasidn
Answered

IDNLearn.com makes it easy to find accurate answers to your questions. Discover in-depth and trustworthy answers to all your questions from our experienced community members.


The time of flight for an object thrown from the rooftop of a tall building is 6.2 seconds. In terms of the initial launch velocity v,
and the angle of launch o, what equation gives you the maximum displacement of the object?

The Time Of Flight For An Object Thrown From The Rooftop Of A Tall Building Is 62 Seconds In Terms Of The Initial Launch Velocity V And The Angle Of Launch O W class=

Sagot :

Lucicidn

Answer:

B . x= v*cos ∅* 6.2

Explanation:

Time of flight of a projectile motion is the time taken by the object to reach the surface from when it was projected.

In this case ;

Initial launch velocity = v

Angle of launch is =∅

Time of flight = 6.2 seconds

The formula for time of flight is;

T= 2*v*sin∅  / g

At time t the displacement components for x and y are;

x= v* t * cos ∅  ----------------i

and

y =u* t * sin ∅ - 1/2 g*t² ------------ii

Taking equation i for displacement of the object in the x component

x = v* t* cos ∅

x = v * cos ∅ * 6.2

x = 6.2* v * cos ∅

Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. Thank you for choosing IDNLearn.com for your queries. We’re here to provide accurate answers, so visit us again soon.