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if a+b+c=0 for a,b,c then prove a²/bc+b²/ca+c²/ab=3.
according to the identity if a+b+c=0 then a3+b3+c3=3abc a3+b3+c3/abc=3 a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3 cancel a,b,c in all the fraction then you get a²/bc+b²/ca+c²/ab=3. hence proved
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