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Find the slope of the line containing the points (0, 3) and (-6, 1)

Sagot :

Step-by-step explanation:

To find the slope of any linear line you would have to use the formula [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex].

(-6 , 1) = ([tex]x_{2}[/tex], [tex]y_{2}[/tex])

(0 , 3) = ([tex]x_{1}[/tex], [tex]y_{1}[/tex])

Now you would insert the values into the formula....

[tex]\frac{1-3}{(-6)-0}[/tex] = [tex]\frac{-2}{-6}[/tex] = [tex]\frac{1}{3}[/tex]

1/3 is your answer.

If you want to check your answer, you would use the formula mx + b= y

m= slope

x = the x-coordinate in either of the coordinates

b= the y-intercept

y = the y-coordinate of the coordinate you chose

mx +b = [tex]\frac{1}{3}[/tex](-6) +3 = -2 +3 = 1

1/3 is the correct answer

Hope this helps!!!