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Answer:
170.4L
Explanation:
The reaction equation is given as:
N₂ + 3H₂ → 2NH₃
Mass of NH₃ = 35.5g
Problem:
How many liters of H₂ are needed to produce 35.5g of NH₃
Solution:
To solve this problem, let us find the number of moles of NH₃;
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of NH₃ = 14 + 3(1) = 17g/mol
So;
Number of moles = [tex]\frac{35.5}{17}[/tex] = 5.07mole
From the balanced reaction equation:
2 mole of NH₃ will be produced from 3 mole of H₂
5.07mole of NH₃ will produce [tex]\frac{5.07 x 3}{2}[/tex] = 7.61mole of H₂
At STP;
1 mole of gas will occupy 22.4L
7.61 mole of H₂ will occupy 7.61 x 22.4 = 170.4L