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A projectile is fired straight up from an initial height of 210 feet, and its height is a function of time, h(t) = -167 + 128t + 210
where h is the height in feet and t is the time in second with t = 0 corresponding to the instant it launches. What is the height 5
seconds after launch? Be sure to include units of measurement.

Sagot :

Answer:

Plug 5 in for t: h(5) = -167 + 128(5) + 210

Step-by-step explanation:

Something feels off about that equation. In linear form, the projectile would continue up infinitely. You sure it wasn't supposed to be h(t) = -167t^2 + 128t + 210?

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