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What is the length of the hypotenuse of a 45°-45°-90° triangle
with leg length 5V3?

Sagot :

Answer:

5[tex]\sqrt{6}[/tex]

Step-by-step explanation:

The easiest way to do this problem is to know that the hypotenuse of a 45-45-90 triangle is equal to [tex]\sqrt{2}[/tex] times the length of a leg.  

So, in your problem the hypotenuse = [tex]\sqrt{2}[/tex](5[tex]\sqrt{3}[/tex]) = 5[tex]\sqrt{6}[/tex].   Another way to solve the problem is to use the Pythagorean theorem, but that is a longer way to solve it.

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