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Answer:
(21 + 11)2 = 64
So, I don't think teachers do this, but this is my way of doing it
Okay, so first, I divided 64 by 2 :
64 ÷ 2 = 32
Then, I subtracted 11 from 32:
21
Now, to check, just do the problem :
(21 + 11)2 = 64
32 * 2 = 64
Answer:
The solutions are:
[tex]m=-3,\:m=-19[/tex]
Step-by-step explanation:
Given the expression
[tex]\left(m\:+11\right)^2=\:64[/tex]
[tex]\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]
solving
[tex]m+11=\sqrt{64}[/tex]
[tex]m+11=\sqrt{8^2}[/tex]
[tex]m+11=8[/tex] ∵ [tex]\sqrt{8^2}=8[/tex]
Subtract 11 from both sides
[tex]m+11-11=8-11[/tex]
Simplify
[tex]m=-3[/tex]
now solving
[tex]m+11=-\sqrt{64}[/tex]
[tex]m+11=-\sqrt{8^2}[/tex]
[tex]m+11=-8[/tex] ∵ [tex]\sqrt{8^2}=8[/tex]
Subtract 11 from both sides
[tex]m+11-11=-8-11[/tex]
Simplify
[tex]m=-19[/tex]
Thus, the solutions are:
[tex]m=-3,\:m=-19[/tex]