IDNLearn.com provides a user-friendly platform for finding and sharing accurate answers. Get step-by-step guidance for all your technical questions from our dedicated community members.
Sagot :
0.98 is the probability of getting 1 Head in 6 tosses.
Probability of getting exactly 1 heads is 0.094.
As a binomial model, there are only two outcomes, the heads & tails
For a coin, the probability of getting heads or tails = 1 /2 = 0.5
Let 'X' be the no of heads obtained
Let :p" be the probability of getting heads
X~Bin (n=6, p = 0.5)
P (X=x) = [tex]nCx * p^{x}* (1-p)^{n-x}[/tex]
P (X=x) = [tex]6Cx* 0.5^{x} * (1-0.5)^{6-x}[/tex]
P (X=x) = [tex]6Cx* 0.5^{x} * (0.5)^{6-x}[/tex]
Note that we need to find probability of getting exactly 1 heads. So we will input the figures
P (X=1) = [tex]6C1 * 0.5^{1} * 0.5^{6-1}[/tex]
P (X=1) = [tex]6C1 * 0.5^{1} * 0.5^{5}[/tex]
P (X=1) = [tex]6 * 0.5 * 0.03125[/tex]
P (X=1) = 0.09375
P (X=1) = 0.094
Therefore, the probability of getting exactly 1 heads is 0.094.
See similar question here
brainly.com/question/19593379
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.