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On a coordinate plane, 2 straight lines are shown. The first solid line has a positive slope and goes through (0, 3) and (3, 4). Everything above the line is shaded. The second dashed line has a positive slope and goes through (0, negative 2) and (1, 1). Everything to the right of the line is shaded.
Which system of linear inequalities is represented by the graph?

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Send2bmgidn

Answer:

A. y≥[tex]\frac{1}{3\\}[/tex]x+3, 3x-y>2

Step-by-step explanation:

The linear equations above match the lines in terms of slope and y-intercept.

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Boffeemadrididn

The system of linear inequalities of the given points is required.

The system of inequality is

[tex]x-3y\leq -9[/tex]

[tex]3x-y>2[/tex]

Points of the first line

[tex](0,3)[/tex]

[tex](3,4)[/tex]

The equation of the line is

[tex]y-3=\dfrac{4-3}{3-0}(x-0)\\\Rightarrow y-3=\dfrac{1}{3}x\\\Rightarrow y-\dfrac{1}{3}x=3\\\Rightarrow 3y-x=9\\\Rightarrow x-3y=-9[/tex]

Let us take a point above this line [tex](2,4)[/tex]

It is also a solid line.

[tex]2-3\times 4=-10<-9[/tex]

So, the inequality is [tex]x-3y\leq -9[/tex]

Points of the second line

[tex](0,-2)[/tex]

[tex](1,1)[/tex]

The equation of the second line is

[tex]y+2=\dfrac{1+2}{1-0}(x-0)\\\Rightarrow y+2=3x\\\Rightarrow 3x-y=2[/tex]

Let us take a point towards the right of the line [tex](2,2)[/tex]

[tex]3\times 2-2=4>2[/tex]

Since, the line is dashed the second inequality will be [tex]3x-y>2[/tex]

Learn more:

https://brainly.com/question/13447558?referrer=searchResults

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