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Two charges that are both 5 C push each other apart with a force of 762,149 N. How far apart are the two charges?

Sagot :

Answer:

543.04 m

Explanation:

The 2 charges are:

q1 = q2 = 5 C

Distance apart is r

Force; F = 762149 N

We will use the formula from coulumbs law;

F = kq1•q2/r²

Where k is coulumbs constant = 8.99 × 10^(9) N.m²/C²

Making r the subject, we have:

r = √((8.99 × 10^(9) × 5 × 5)/762149)

r ≈ 543.04 m

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